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what are the available colleges for 86.35 percentile in jee paper 2,2020


Vishwas Kanumalli 26th Jan, 2020
Answers (2)
Rishi Garg 26th Jan, 2020

You can calculate your rank in JEE Main Paper 2 using the formula:Rank = (100-percentile)*(No. of students appeared for the examination)/100As the no. of students appeared for Paper 2 (Jan) are around 112679, your rank will be around 21500. However as the no. of students in April changes, your rank will change according to that.With this rank, there are less chances of getting a NIT but you may get some other architecture colleges. On the extreme case, you may also get NIT Hamirpur with Architecture branch. To check the list of all colleges which you may get with this percentile, kindly use the link provided below:

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For more information regarding the same, kindly use the B.Tech companion from the link given:

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1 Comment
Comments (1)
26th Jan, 2020
Thanks for your reply
Reply
AYAN MULLA 26th Jan, 2020

HELLO VISHWAS

It is very difficult to predict the actual rank since it depends on many factors . So the expected rank for your percentile for the january session comes out to be  118619.The expected rank might change depending on the no of students appearing the april session.

NOw getting into top 5 NITs is very difficult with this percentile But do not worry since you have an april attempt left and obtaining a percentile above 85 means you have a very descent chance for qualifying JEE mains which means IITS are waiting for you.

Now coming to your question which college you might get then you can use our college predictor which has following features.

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2 Comments
Comments (2)
26th Jan, 2020
Thanks for your reply
Reply
27th Jan, 2020
Vishwas Kanumalli sorry bimistakely i gave the answer thinking of paper 1 in mind.
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