(x + a) (x + b) = x² + (a + b)x + ab
(x + y + z)² = x²+ y²+ z² + 2xy + 2yz + 2zx
x³ + y³ + z³ – 3xyz = (x + y + z)(x² + y² + z² – xy – yz – zx)
Question : Compute the expression (299)² using algebraic identities.
Option 1: 89301
Option 2: 89402
Option 3: 88401
Option 4: 89401
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