Hi dear,
Hope you are doing well!

Now let's go through your question.

Hopefully you will be knowing that The cutoff of AEEE vary for different categories and branches that are offered across three campuses of Amrita Vishwa Vidyapeetham.
The cutoff will consist of opening and closing ranks. The closing rank will be the minimum score a candidate needs to obtain to be eligible for admission process.

Here's the CUTOFF of 2018:

• SC/ST Category (Open & State Quota)1 - 15000(OR)    15001-  25000(CR)
• General Category (Open & State Quota)1-  750(OR)    9501 - 10000(CR)
• State Quota     10001 - 12500(OR)     20001- 22500(CR)

Hope it helps!

Thank You!

Hi!
The previous year cut-off ranks as released by the Bangalore campus for the year 2018-2019 for SC are

• Computer science and engineering - 15500
• Electricals & electronics engineering- 17000
• Electronics and communication engineering- 15700
• Electronics & instrumentation engineering- 17700
• Mechanical engineering- 15700

Kindly note that there were the closing cut-off ranks for the year 2018-2019
For further information visit the website mentioned below.
http://www.toppr.com/bytes/amrita-university/
Hope this helps!

Shreyas,

to secure your seat in Amrita Vishwa Vidyapeetham University, Coimbatore, you need to clear the AEEE entrance exam which is a 2 and a half hour exam which comprises of 100 questions- 

Physics-30

Chemistry-30

Mathematics-40

The cutoff for last year i.e. 2018 AEEE exam for SC category was-

Opening rank - 1 to 15000

Closing rank - 15001 to 25000

So, try to secure a rank in the top 30000 atleast so that even if the cutoff fluctuates this year, you still have a good chance of selection.

Feel free to ask any more queries.

All the best!!!

Amrita Vishwa Vidyapeetham, Coimbatore

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