Question : What is the length of the longest rod that can be placed in a room of dimensions 12 m × 9 m × 8 m?
Option 1: 15 m
Option 2: 17 m
Option 3: 16 m
Option 4: 14 m
Correct Answer: 17 m
Solution : Given: Dimension of the room = 12 m × 9 m × 8 m Length of the longest rod= $\sqrt{l^2+b^2+h^2}$ [where $l,b,h$ are length, breadth, and height respectively.] = $\sqrt{12^2+9^2+8^2}$ = $\sqrt{144+81+64}$ = $\sqrt{289}=17$ Hence, the correct answer is 17 m.
Application | Eligibility | Selection Process | Result | Cutoff | Admit Card | Preparation Tips
Question : The longest rod that can be placed in a room is 12 metres long, 9 metres broad, and 8 metres high is:
Option 1: 27 m
Option 2: 19 m
Option 3: 17 m
Option 4: 13 m
Question : The value of $\frac{2}{3} \div \frac{3}{10}$ of $\frac{4}{9}-\frac{4}{5} \times 1 \frac{1}{9} \div \frac{8}{15}+\frac{3}{4} \div \frac{1}{2}$ is:
Option 1: $\frac{29}{6}$
Option 2: $\frac{17}{9}$
Option 3: $\frac{14}{3}$
Option 4: $\frac{49}{12}$
Question : The value of $\frac{2}{3} \div \frac{3}{10}$ of $\frac{4}{9}-\frac{4}{5} \times 1 \frac{1}{9} \div \frac{8}{15}-\frac{3}{4}+\frac{3}{4} \div \frac{1}{2}$ is:
Option 1: $\frac{25}{6}$
Option 2: $\frac{14}{3}$
Option 3: $\frac{17}{9}$
Question : What is the length (in metres) of the longest rod that can be placed in a room which is 2 metre long, 2 metre broad, and 6 metre high?
Option 1: $8$
Option 2: $2\sqrt{11}$
Option 3: $3\sqrt{11}$
Option 4: $10$
Question : What is the dimension of the kabaddi playing field for men?
Option 1: 14 m × 10 m
Option 2: 14 m × 8 m
Option 3: 12.50 m × 10 m
Option 4: 13 m × 10 m
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile