Question : What is the sum of the first 9 terms of an arithmetic progression, if the first term is 7 and the last term is 55?
Option 1: 219
Option 2: 137
Option 3: 231
Option 4: 279
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Correct Answer: 279
Solution : Given: The first term is 7 and the last term is 55. Using the formula, S9 = $\frac{n}{2}(a+l)$ Where $a$ is the first term, $l$ is the last term of the A.P., and n is the number of terms. By putting the value of 1st and last term, ⇒ S9 = $\frac{9}{2}$(7 + 55) ⇒ S9 = $\frac{9}{2}$ × 62 $\therefore$ S9 = 9 × 31 = 279 Hence, the correct answer is 279.
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Question : The sum of 10 terms of the arithmetic series is 390. If the third term of the series is 19, find the first term:
Option 1: 3
Option 2: 5
Option 3: 7
Option 4: 8
Question : If 7 times the 7th term of an arithmetic progression (A.P.) is equal to 11 times its 11th term, then the 18th term of the A.P. will be:
Option 1: 1
Option 2: 0
Option 3: 2
Option 4: –1
Question : The 3rd and 8th terms of an Arithmetic progression are –14 and 1, respectively. What is the 11th term?
Option 1: 14
Option 2: 16
Option 3: 20
Option 4: 10
Question : The sum of the first 20 term of the series $\frac{1}{5×6}+\frac{1}{6×7}+\frac{1}{7×8}+....$ is:
Option 1: 0.16
Option 2: 1.6
Option 3: 16
Option 4: 0.016
Question : The sum of two numbers is equal to 25 and their difference is 20. The ratio of the two numbers is:
Option 1: 9 : 1
Option 2: 7 : 9
Option 3: 3 : 5
Option 4: 2 : 7
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