Question : What is the value of (22 + 1)(24+1)(28 + 1)(216 + 1) .........(2128 + 1)?
Option 1: $\frac{2^{256}-1}{2}$
Option 2: $\frac{2^{256}-1}{3}$
Option 3: $2^{256}-1$
Option 4: $\frac{2^{256}-1}{4}$
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Correct Answer: $\frac{2^{256}-1}{3}$
Solution : $(2^2 + 1) (2^4 + 1) (2^8 + 1) (2^{16} + 1) ........ (2^{128} + 1)$ Divide by $(2^2 - 1)$ in numerator and denominator = $\frac{1}{(2^2 - 1)}[(2^2 - 1)(2^2 + 1) (2^4 + 1) (2^8 + 1) (2^{16} + 1) ........ (2^{128} + 1)]$ = $\frac{1}{(2^2 - 1)}[(2^4 - 1) (2^4 + 1) (2^8 + 1) (2^{16} + 1) ........ (2^{128} + 1)]$ = $\frac{1}{(2^2 - 1)}[(2^8 - 1) (2^8 + 1) (2^{16} + 1) ........ (2^{128} + 1)]$ = $\frac{1}{(2^2 - 1)}[(2^{16} - 1) (2^{16} + 1) ........ (2^{128} + 1)]$ = $\frac{1}{(2^2 - 1)}(2^{256} - 1)$ = $\frac{(2^{256} - 1)}{3}$ Hence, the correct answer is $\frac{(2^{256} - 1)}{3}$.
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Question : Find the value of the given expression: $\frac{(4\frac{1}{3}+3\frac{1}{3}\times 1\frac{4}{5}\div 3\frac{3}{4}\times (1\frac{1}{2}+1\frac{1}{3}))}{(\frac{2}{3}\div \frac{5}{6}\times \frac{2}{3})}$
Option 1: $11 \frac{3}{8}$
Option 2: $10\frac{1}{8}$
Option 3: $14\frac{3}{8}$
Option 4: $16\frac{5}{8}$
Question : If $x+\frac{1}{x}=\mathrm{\frac{K}{2}}$, then what is the value of $\frac{x^8+1}{x^4} ?$
Option 1: $\frac{\mathrm{K}^4-16 \mathrm{~K}^2+32}{16}$
Option 2: $\frac{\mathrm{K}^4-8 \mathrm{~K}^2-36}{32}$
Option 3: $\frac{\mathrm{K}^4-8 \mathrm{~K}^2-32}{16}$
Option 4: $\frac{\mathrm{K}^4-8 \mathrm{~K}^2+32}{16}$
Question : What is the value of $\left(\mathrm{k}+\frac{1}{\mathrm{k}}\right)\left(\mathrm{k}-\frac{1}{\mathrm{k}}\right)\left(\mathrm{k}^2+\frac{1}{\mathrm{k}^2}\right)\left(\mathrm{k}^4+\frac{1}{\mathrm{k}^4}\right)$?
Option 1: $\mathrm{k}^{16}+\frac{1}{\mathrm{k}^{16}}$
Option 2: $\mathrm{k}^{16}-\frac{1}{\mathrm{k}^{16}}$
Option 3: $\mathrm{k}^8-\frac{1}{\mathrm{k}^8}$
Option 4: $\mathrm{k}^8+\frac{1}{\mathrm{k}^8}$
Question : If $x+\frac{1}{x}=2 K$, then what is the value of $x^4+\frac{1}{x^4}$?
Option 1: $16 {K}^4-16 {K}^2-1$
Option 2: $8 {K}^4+4 {K}^2-1$
Option 3: $16 {K}^4-16 {K}^2+2$
Option 4: $16 {K}^4-4 {K}^2-1$
Question : The value of $\frac{3+8 \times 8 \div 8 \text { of } 8+7 \div 7 \times 2}{5 \div 5 \text { of } 4+3 \times 3 \div 3-3+2}$ is:
Option 1: $1 \frac{3}{5}$
Option 2: $2 \frac{2}{3}$
Option 3: $1 \frac{4}{7}$
Option 4: $2 \frac{3}{7}$
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