Question : What is the value of $\frac{1+\sin A}{\cos ^2 A}$?
Option 1: $\frac{1}{1-\sin A}$
Option 2: $\frac{1}{1+\sin A}$
Option 3: $\frac{1}{1+\cos A}$
Option 4: $\frac{1}{1-\cos A}$
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Correct Answer: $\frac{1}{1-\sin A}$
Solution : $\frac{1+\sin A}{\cos ^2 A}$ = $\frac{1+\sin A}{1-\sin^2 A}$ = $\frac{1+\sin A}{(1-\sin A)(1+\sin A)}$ = $\frac{1}{1-\sin A}$ Hence, the correct answer is $\frac{1}{1-\sin A}$.
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Question : If $\sin A-\cos A=\frac{\sqrt{3}-1}{2}$, then the value of $\sin A\cdot \cos A$ is:
Option 1: $\frac{\sqrt{3}}{2}$
Option 2: $\frac{3}{2}$
Option 3: $\frac{\sqrt{3}}{4}$
Option 4: $\frac{1}{\sqrt{3}}$
Question : If $\sin A+\sin ^2 A=1$, then the value of the expression $\left(\cos ^2 A+\cos ^4 A\right)$ is
Option 1: $\frac{3}{2}$
Option 2: $1$
Option 3: $2$
Option 4: $\frac{1}{2}$
Question : What is the value of $\frac{\sin \theta+\cos \theta}{\sin \theta-\cos \theta}+\frac{\sin \theta-\cos \theta}{\sin \theta+\cos \theta}$?
Option 1: $\frac{1}{\left(\sin ^2 \theta-\cos ^2 \theta\right)}$
Option 2: $2\left(\sin ^2 \theta-\cos ^2 \theta\right)$
Option 3: $\frac{2}{\left(\sin ^2 \theta-\cos ^2 \theta\right)}$
Option 4: $\sin ^2 \theta-\cos ^2 \theta$
Question : If $\sin \theta \cos \theta=\frac{1}{\sqrt{3}}$ then the value of $\left(\sin ^4 \theta+\cos ^4 \theta\right)$ is:
Option 1: $1$
Option 2: $\frac{5}{3}$
Option 3: $\frac{2}{3}$
Option 4: $\frac{1}{3}$
Question : If $\frac{\sin\theta+\cos\theta}{\sin\theta-\cos\theta}=3$, then the value of $\sin^{4}\theta$ is:
Option 1: $\frac{2}{5}$
Option 2: $\frac{1}{5}$
Option 3: $\frac{16}{25}$
Option 4: $\frac{3}{5}$
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