Question : What is the value of $\frac{1+\mathrm{x}}{1-\mathrm{x}^2} \div \frac{1+\mathrm{x}}{1-\mathrm{x}^4}-\frac{1-\mathrm{x}^4}{1-\mathrm{x}} \times \frac{1+\mathrm{x}}{1-\mathrm{x}^2}$?
Option 1: $\frac{2 \mathrm{x}\left(1+\mathrm{x}^2\right)}{(1-\mathrm{x})}$
Option 2: $\frac{2 \mathrm{x}\left(1+\mathrm{x}^2\right)}{(\mathrm{x}-1)}$
Option 3: $(1-\mathrm{x})^2$
Option 4: $\left(1+\mathrm{x}^2\right)$
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Correct Answer: $\frac{2 \mathrm{x}\left(1+\mathrm{x}^2\right)}{(\mathrm{x}-1)}$
Solution : Given expression, $\frac{1+\mathrm{x}}{1-\mathrm{x}^2} \div \frac{1+\mathrm{x}}{1-\mathrm{x}^4}-\frac{1-\mathrm{x}^4}{1-\mathrm{x}} \times \frac{1+\mathrm{x}}{1-\mathrm{x}^2}$ $=\frac{\frac{1+\mathrm{x}}{1-\mathrm{x}^2}}{\frac{1+\mathrm{x}}{1-\mathrm{x}^4}}-\frac{(1-\mathrm{x}^2)(1+\mathrm{x}^2)\times(1+\mathrm{x})}{(1-\mathrm{x})\times(1-\mathrm{x}^2)}$ $=\frac{(1+\mathrm{x})(1-\mathrm{x}^4)}{(1-\mathrm{x}^2)(1+\mathrm{x})}-\frac{(1+\mathrm{x}^2)(1+\mathrm{x})}{1-\mathrm{x}}$ $=\frac{(1+\mathrm{x})(1-\mathrm{x^2})(1+\mathrm{x^2})}{(1-\mathrm{x^2})(1+\mathrm{x})}-\frac{(1+\mathrm{x}^2)(1+\mathrm{x})}{1-\mathrm{x}}$ $=\small 1+\mathrm{x^2}-\frac{(1+\mathrm{x}^2)(1+\mathrm{x})}{1-\mathrm{x}}$ $=\small (1+\mathrm{x^2})\times\frac{1-\mathrm{x}-1-\mathrm{x}}{1-\mathrm{x}}$ $=\frac{-2\mathrm{x}(1+\mathrm{x^2})}{1-\mathrm{x}}$ $=\frac{2\mathrm{x}(1+\mathrm{x^2})}{\mathrm{x}-1}$ Hence, the correct answer is $\frac{2\mathrm{x}(1+\mathrm{x^2})}{\mathrm{x}-1}$.
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Question : What is the value of $\left(\mathrm{k}+\frac{1}{\mathrm{k}}\right)\left(\mathrm{k}-\frac{1}{\mathrm{k}}\right)\left(\mathrm{k}^2+\frac{1}{\mathrm{k}^2}\right)\left(\mathrm{k}^4+\frac{1}{\mathrm{k}^4}\right)$?
Option 1: $\mathrm{k}^{16}+\frac{1}{\mathrm{k}^{16}}$
Option 2: $\mathrm{k}^{16}-\frac{1}{\mathrm{k}^{16}}$
Option 3: $\mathrm{k}^8-\frac{1}{\mathrm{k}^8}$
Option 4: $\mathrm{k}^8+\frac{1}{\mathrm{k}^8}$
Question : The value of $2 \frac{3}{5} \div\left[2 \frac{1}{3} \div\left\{4 \frac{1}{3}-\left(2 \frac{1}{2}+\frac{2}{3}\right)\right\}\right]$ is equal to:
Option 1: $1 \frac{3}{10}$
Option 2: $2 \frac{7}{10}$
Option 3: $2 \frac{3}{7}$
Option 4: $1 \frac{3}{7}$
Question : The value of $\left(\frac{2+7 \times 7 \div 9 \text { of } 9+6 \div 6 \times 2}{4 \div 4 \text { of } 5+7 \times 7 \div 7-6+4}\right)$ is:
Option 1: $\frac{1734}{2407}$
Option 2: $\frac{1865}{2106}$
Option 3: $\frac{1857}{2507}$
Option 4: $\frac{1664}{2305}$
Question : What is the value of $\frac{7 \times 4 \div 8}{5 \times 25 \div 125}+\frac{5 \times 4 \div 8}{8 \times 4 \div 16}-\frac{7 \times 4 \div 2}{8 \times 7 \div 4}$?
Option 1: $4$
Option 2: $\frac{13}{4}$
Option 3: $\frac{15}{4}$
Option 4: $\frac{9}{2}$
Question : If $x+\frac{1}{x}=\mathrm{\frac{K}{2}}$, then what is the value of $\frac{x^8+1}{x^4} ?$
Option 1: $\frac{\mathrm{K}^4-16 \mathrm{~K}^2+32}{16}$
Option 2: $\frac{\mathrm{K}^4-8 \mathrm{~K}^2-36}{32}$
Option 3: $\frac{\mathrm{K}^4-8 \mathrm{~K}^2-32}{16}$
Option 4: $\frac{\mathrm{K}^4-8 \mathrm{~K}^2+32}{16}$
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