Question : What is the value of $\frac{(0.91)^3+(0.09)^3}{ [(0.91)^2-0.0819+(0.09)^2]}$?
Option 1: 1
Option 2: 5
Option 3: 4
Option 4: 6
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Correct Answer: 1
Solution : Using $(a^3+b^3)=(a+b)(a^2+b^2-ab)$ $\frac{(0.91)^3+(0.09)^3}{ [(0.91)^2-0.0819+(0.09)^2]}$ = $\frac{(0.91+0.09)[(0.91)^2-0.0819+(0.09)^2]}{ [(0.91)^2-0.0819+(0.09)^2]}$ = 0.91 + 0.09 = 1 Hence, the correct answer is 1.
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Question : If $x=(\sqrt{6}-1)^{\frac{1}{3}}$, then the value of $\left(x-\frac{1}{x}\right)^3+3\left(x-\frac{1}{x}\right)$ is:
Option 1: $\frac{2 \sqrt{6}-6}{5}$
Option 2: $\frac{4 \sqrt{6}-6}{5}$
Option 3: $\frac{4 \sqrt{6}-6}{3}$
Option 4: $\frac{4 \sqrt{3}-6}{5}$
Question : If $\sec\theta +\tan\theta = 3$, then what is the value of $\sec \theta-\tan \theta$?
Option 1: $\frac{1}{3}$
Option 2: $6$
Option 3: $\frac{1}{6}$
Option 4: $\frac{1}{5}$
Question : The value of $3\frac{1}{2} - [2\frac{1}{4}+ 1\frac{1}{4} - \frac{1}{2}(1\frac{1}{2}-\frac{1}{3} -\frac{1}{6})]$ is:
Option 1: $\frac{1}{2}$
Option 2: $2\frac{1}{2}$
Option 3: $3\frac{1}{2}$
Option 4: $9\frac{1}{2}$
Question : What is the value of $\frac{\frac{5}{6} \text { of } \frac{1}{3} \times \frac{12}{25}-\frac{1}{3} \text { of } \frac{5}{6} \times \frac{18}{25}}{\frac{25}{12} \text { of } \frac{1}{6} \times \frac{2}{5}+\frac{3}{8} \text { of } \frac{12}{25} \times \frac{5}{6}}$?
Option 1: $-\frac{3}{13}$
Option 2: $-\frac{5}{13}$
Option 3: $-\frac{8}{25}$
Option 4: $-\frac{3}{25}$
Question : The value of exponential form of $\sqrt{\sqrt{2}\sqrt{3}}$ is:
Option 1: $6$
Option 2: $6^{\frac{1}{2}}$
Option 3: $6^{-\frac{1}{2}}$
Option 4: $6^{\frac{1}{4}}$
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