Question : What is the value of a2 + b2 + c2, if a + b + c = 9 and ab + bc + ca = 23 ?
Option 1: 22
Option 2: 32
Option 3: 49
Option 4: 35
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Correct Answer: 35
Solution : Given: a + b + c = 9 and ab + bc + ca = 23 Squaring on both sides, ⇒ (a + b + c)2 = 92 ⇒ a2 + b2 + c2 + 2(ab + bc + ca) = 81 ⇒ a2 + b2 + c2 = 81 – (2 × 23) = 81 – 46 = 35 Hence, the correct answer is 35.
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Question : What is the possible value of (a + b + c) – 3, if a2 + b2 + c2 = 9 and ab + bc + ca = 8?
Option 1: 5
Option 2: 3
Option 3: 9
Option 4: 2
Question : If a + b + c = 1, ab + bc + ca = –22 and abc = –40, then what is the value of a3 + b3 + c3 ?
Option 1: 67
Option 2: –53
Option 3: –51
Option 4: 27
Question : If $a+b+c$ = 6 and $ab+bc+ca$ = 11, then the value of $bc(b+c)+ca(c+a)+ab(a+b)+3abc$ is:
Option 1: 33
Option 2: 66
Option 3: 55
Option 4: 23
Question : If $\frac{a^{2} - bc}{a^{2}+bc}+\frac{b^{2}-ca}{b^{2}+ca}+\frac{c^{2}-ab}{c^{2}+ab}=1$, then the value of $\frac{a^{2}}{a^{2}+bc}+\frac{b^{2}}{b^{2}+ac}+\frac{c^{2}}{c^{2}+ab}$ is:
Option 1: 0
Option 2: 1
Option 3: –1
Question : What is the value of ${a}^3+{b}^3+{c}^3$ if $(a+b+c)=0$?
Option 1: $a^2+b^2+c^2-3abc$
Option 2: $0$
Option 3: $3abc$
Option 4: $a^2+b^2+c^2-ab-bc-ca$
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