Question : What is the value of $\left(\frac{1}{a} - \frac{1}{b} - \frac{1}{c}\right)$, if $\frac{2a - 5}{a} - \frac{4b - 5}{b} + \frac{6c + 5}{c} = 0$?
Option 1: $\frac{4}{5}$
Option 2: $-\frac{8}{5}$
Option 3: $\frac{2}{5}$
Option 4: $-\frac{12}{5}$
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Correct Answer: $\frac{4}{5}$
Solution : $\frac{2a- 5}{a} - \frac{4b - 5}{b} + \frac{6c + 5}{c} = 0$ $⇒(2 -\frac{5}{a}) - (4 - \frac{5}{b}) + (6 + \frac{5}{c})=0$ $⇒ -\frac{5}{a} + \frac{5}{b} + \frac{5}{c} = -4$ $⇒–(\frac{1}{a}- \frac{1}{b} - \frac{1}{c}) =-\frac{4}{5}$ $\therefore(\frac{1}{a} - \frac{1}{b} - \frac{1}{c}) = \frac{4}{5}$ Hence, the correct answer is $\frac{4}{5}$.
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Question : The value of $15 \div 8-\frac{5}{4}$ of $\left(\frac{8}{3} \times \frac{9}{16}\right)+\left(\frac{9}{8} \times \frac{3}{4}\right)-\left(\frac{5}{32} \div \frac{5}{7}\right)+\frac{3}{8}$ is:
Option 1: 0
Option 2: 1
Option 3: 2
Option 4: 3
Question : If $M =\left ( \frac{3}{7} \right ) ÷ \left ( \frac{6}{5} \right ) ×\left ( \frac{2}{3} \right ) + \left ( \frac{1}{5} \right ) ×\left ( \frac{3}{2} \right )$ and $N = \left ( \frac{2}{5} \right ) × \left ( \frac{5}{6} \right ) ÷ \left ( \frac{1}{3} \right ) + \left ( \frac{3}{5} \right ) × \left ( \frac{2}{3} \right ) ÷ \left ( \frac{3}{5} \right )$, then what is the value of $\frac{M}{N}$?
Option 1: $\frac{207}{560}$
Option 2: $\frac{339}{1120}$
Option 3: $\frac{113}{350}$
Option 4: $\frac{69}{175}$
Question : If $\left (a+\frac{1}{b} \right)=1$ and $\left (b+\frac{1}{c} \right)=1$, the value of $\left (c+\frac{1}{a} \right)$ is:
Option 3: – 1
Option 4: 2
Question : If $x^{2} -3x +1=0$, then the value of $\frac{\left(x^4+\frac{1}{x^2}\right)}{\left(x^2+5 x+1\right)}$ is:
Option 1: $\frac{9}{4}$
Option 2: $\frac{27}{8}$
Option 3: $\frac{5}{2}$
Option 4: $2$
Question : If $2x+\frac{1}{2x}=2,$ what is the value of $\sqrt{2\left (\frac{1}{x}\right)^{4}+\left (\frac{1}{x}\right)^{5}}\; ?$
Option 1: 1
Option 2: 2
Option 3: 4
Option 4: 8
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