There is no value present at the tenth thousand place in number 47, so it will be 0.
Question : In a two-digit number, the digit at unit's place is 1 less than twice the digit at the ten's place. If the digit at unit's and ten's place are interchanged, the difference between the new and the original number is less than the original number by 20. The original number is:
Option 1: $59$
Option 2: $23$
Option 3: $35$
Option 4: $47$
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