Hi,

I hope you are doing good. As you are giving your second attempt as a private candidate, you will be required to register for the board exam through there official website. After successful registration, you will be asked to submit certain important documents like ID proof, latest photograph etc.

Hi, CHINNUHEMANTH373

Now we know that

Rank will be given according to the formula

R= {(%KCET+%QE)/200}×100

with 65 marks in KCET you're having a percentage of 36.11% ((65/180)*100)

& then in boards you have a percentage of 95 % ((285/300)*100)

adding both percentages you have a total of 95+36.11= 131.11

Ur ranking in kcet will be around 15000 to 20000 all the best

Hello Aspirant,

I hope you are doing well.

According to the information you provided in the question, your overall score in KCET 2021 will be 50.

According on the calculations above, your KCET 2021 rank is projected to be in the 30000-40000 range. However, keep in mind that this is

Hi dear,

You have scored a decent score in WBJEE entrance exam and don't worry you can get decent Colleges. You can predict Colleges you can get using the predictor given below. But cut-offs changes from year to year and depends on many factors like

**Number of seats available

**Caste

Hi, so your kcet score is (62/180)*100=34.4%. Then you pcm score is (216/300)*100=72%.

Therefore,

Rank will be given as,

R= {(%KCET+%QE)/200}×100

Which is,

(34.4+72)/200*100=53.2%

You can probably expect any rank from 10,000 to 20,000.

Hello Aspirant,

As per the marks mentioned by you in the question your rank in KCET 2022 is expected to be under 3500-4000 .  But note that this is not your exact rank because it is not yet released and the rank predicted above is on the basis of previous

You can appear for the CLAT examination 2024 just by applying the CLAT application form available for the CLAT 2024 which will be released in the year 2024. So there are no such obligations that you can only give examination in the year of 10+2. I would recommend you to

In usual times, the eligibility criteria for JEE Main examination is as follows:

1. Minimum 75% marks in XII (General)

2. Minimum 65% marks in XII (SC/ST/PwD)

But due to the COIV-19 pandemic, National Testing Agency has removed the minimum marks in class XII requirement for JEE Main for the

Hello there!

SASTRA has not mentioned any cutoff criteria for JEE MAINS score as they have their own merit list for allotting seats for admission in this university. If you want to pursue your B.Tech in SASTRA with CSE branch, you need a score of 95% and above in your