Cheating in Examination
Hi,
Since it is given that van der waal's constant
b= 81 ml/ mol
And we have a formula that goes like
b=4 × volume of 1 mol molecule
b=4Na (4/3πr^3)
Therefore,
r= (3b/16Naπ)^1/3
r=(243/302.59×10^23)^1/3
r~(0.80×10^-23)^1/3
r~ 4.3×10^-7 cm
D= 8.6×10^-7 cm (approx)
Hope it helps!
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