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Heat of combustion at constant volume (ΔE)

Δ E= heat capacity * Δ T* moles

Δ E = 17.7*0.5*16/0.16

by solving the abouve equation,we get Δ E= -885 kJ/mole

Heat of combustion at constant pressure Δ H=Δ E+Δ ngRT

Reaction for Combustion of Methane is CH4+2O2 gives rise to CO2+2H2O(l)

Δng= -2,R=8.314*10^-3Kj/mol k,T=300K

Δ H= -885-2*8.314*10^-3*300

By solving thus we get Δ H= -890KJ

Hope it helps!!!!