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1g sample of CaCO3 react with 10ml of 2M HCl solution.unused HCl require 100ml of 0.1M NaOH for complete neutralisation


Piyush keshri 17th May, 2018
Answer (1)
yash raj 19th May, 2018

hello piyush 

This is a case of limiting reagent, limiting reagents are those reagents which  control the amount of product formed by depleting earlier. 

from reaction of HCL and NaOH we found the HCL left was =0.01 moles

total HCL provided was=0.02 moles

so HCL consumed was =0.01 moles

so moles of CaCO3 used= 0.005 , which is half the no of moles of CaCO3 provided.

so % purity =50%


hope it helps

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