228 Views

4. A steel rod having circular cross section with diameter 5 cm and length 3 m is utilized to hang a block of 100 kg at its free end. Its upper end is fixed with the ceiling. Steel density is 8000kg/m3 . Find the total elongation of the rod, taking into account its own weight. Take E = 210 GPa.


rahulattri0190 21st Dec, 2020
Answer (1)
Ayush 30th Dec, 2020

Hello Candidate,

The formula for Young's Modulus of Elasticity for steel is given by: Y= Mass Attached* Length/ Elongation* Area of Cross Section.

Here, the value of Young's Modulus=21000 Pascal, Mass Attached=100 kg, Length=3 metres, Area of Cross Section= 22/7*5*5 cm2= .0019 metres2. So, elongation= 1000*3/ .0019*21000= 75.18 metres.

Hope that this answer helps you.

Thank You.

Related Questions

Amity University-Noida B.Tech...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Narayana Business School MBA/...
Apply
Top 30 Private B-Schools Nationally and Top 3 in Gujarat | Highest CTC- 20 LPA | Average CTC- 8.4 LPA | 40% Pre-Placement Offers | 670+ Recruiters 
JAGSoM PGDM Admissions 2026
Apply
Highest CTC 51.38 LPA | Median CTC 10.32 LPA | Top 25% Average CTC 14.32 LPA
IFMR Graduate School of Busin...
Apply
UGC Approved Programs | Near 100% Placement Record | Up to 100% Scholarships | Highest CTC 21.32 LPA
Amity University-Noida Law Ad...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Great Lakes Institute of Mana...
Apply
Globally Recognized by AACSB (US) & AMBA (UK) | 17.8 LPA Avg. CTC for PGPM 2025
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books