Question : $16 \sec ^2 A-16 \tan ^2 A=$_________.
Option 1: 9
Option 2: 0
Option 3: 16
Option 4: 1
Correct Answer: 16
Solution : Given expression, $16 \sec ^2 A-16 \tan ^2 A$ $= 16(\sec^2A-\tan^2A)$ $= 16 × (1)$ $= 16$ Hence, the correct answer is 16.
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Question : Find the value of $\left(\tan ^2 \theta+\tan ^4 \theta\right)$.
Option 1: $\cot ^2 \theta-\tan ^2 \theta$
Option 2: $\ {\sec}^4 \theta-\ {\sec}^2 \theta$
Option 3: $\ {\sec}^4 \theta-\ {\sec}^4 \theta$
Option 4: $ \ {\sec}^4 \theta+\ {\sec}^2 \theta$
Question : If $\cos\theta=\frac{3}{5}$, then the value of $\sin\theta.\sec\theta.\tan\theta$ is:
Option 1: $\frac{9}{16}$
Option 2: $\frac{16}{9}$
Option 3: $\frac{3}{4}$
Option 4: $\frac{4}{3}$
Question : The value of (1 + cot A – cosec A)(1 + tan A + sec A) – 1 is:
Option 1: 1
Option 2: 2
Option 3: 3
Option 4: 0
Question : If $\sec x+\cos x=2$, then the value of $\sec^{16} x+\cos^{16} x$ will be:
Option 1: $\sqrt3$
Option 2: $2$
Option 3: $1$
Option 4: $0$
Question : The value of $\sqrt{\frac{1+\sin A}{1-\sin A}}$ is:
Option 1: $\sec A-\tan A$
Option 2: $\operatorname{cosec} A+\cot A$
Option 3: $\sec A+\tan A$
Option 4: $\operatorname{cosec} A-\cot A$
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