Hello,

When 5 dice are thrown at a time the total set of possibilities =(6)^5

Coming to solve the problem 

1.same number on max 2 dice:

That gives same number on two dice and all the other three different or all the 5 dice with different numbers=(6c1)*1*5*4*3 +6*5*4*3*2

The probability

={(6c1)*1*5*4*3 +6*5*4*3*2} /{(6) ^5}

2.same number on min 2 dice 

That can be solved by 1 minus the probability with all the numbers on dice being different 

The probability = 1- (6*5*4*3*2)/{(6) ^5}

Hope this helps.....