hello!!!

As per the problem given

initial velocity of the ball is 0 m/s

final velocity of the ball is 60 m/s (given)

v2-u2=2gh

60^2-0^2=2x10xh

h=180m

h = 1/2gt ²

180=1/2x10xt ²

360/10=t ²

t=6sec

height  travelled in last second = height travelled in 6 seconds - height travelled in 5 seconds

=1/2x10x36 -1/2x10x25

=36x5 - 25x5

=55m

height travelled by the ball in last one second = 55 m

THANK YOU!!!!!!!