483 Views

a block of mass M is placed on an ideal spring and equilibrium the spring is compressed by x loot in equilibrium. if the spring is further compressed by 2x then find the time period of oscillation


1111rajneesh1111 21st Jan, 2021
Answer (1)
Ayush 21st Jan, 2021

Hello candidate,

In spring mass system, the time period refers to the time required for the spring to regain its original shape after compressing or extending from its natural length.

The expression for time period is given by the formula T=2π×√m/k, which is clearly independent of the the extension produced. So, the time period of oscillation will remain same irrespective of the extension being extended to 2x.

Hope it helps!!

Related Questions

MAHE Manipal M.Tech 2025
Apply
NAAC A++ Accredited | Accorded institution of Eminence by Govt. of India | NIRF Rank #4
Graphic Era (Deemed to be Uni...
Apply
NAAC A+ Grade | Among top 100 universities of India (NIRF 2024) | 40 crore+ scholarships distributed
Amity University Noida B.Tech...
Apply
Among Top 30 National Universities for Engineering (NIRF 2024) | 30+ Specializations | AI Powered Learning & State-of-the-Art Facilities
JSS University Mysore BBA Adm...
Apply
NAAC A++ Accredited| Ranked #24 in University Category by NIRF
JSS University Noida MBA 2025
Apply
170+ Recruiters Including Samsung, Zomato, LG, Adobe and many more | Highest CTC 47 LPA
UPES B.Tech Admissions 2025
Apply
Ranked #42 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements | Last Date to Apply: 29th May
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books