748 Views

a body mass 0.4 kg is whirled in a horizontal circle of radius 5 m it is performed 120 RPM the force acting on it is


gunjalrohini23 24th Oct, 2021
Answer (1)
Rohith Miryala 24th Oct, 2021

Hello Rohini,

w= 120*2*pie / 60 =4*pie rad/sec

radius=5 m ,  mass=0.1 kg

centripetal force=m*v^2/ r

=m*w^2*r

=32(pie)^2  newton

=315.8 N

This is the answer of the question you have asked.

Hope this helps..

Related Questions

Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates and judiciaries
Amity University Noida B.Tech...
Apply
Among Top 30 National Universities for Engineering (NIRF 2024) | 30+ Specializations | AI Powered Learning & State-of-the-Art Facilities
Amity University Noida MBA Ad...
Apply
Amongst top 3% universities globally (QS Rankings) | Ranked among top 10 B-Schools in India by multiple publications
Amity University, Noida BBA A...
Apply
Ranked amongst top 3% universities globally (QS Rankings)
MAHE Online MBA
Apply
Apply for Online MBA from Manipal Academy of Higher Education (MAHE)
FLAME University | MBA 2026
Apply
NAAC A++ Grade | MBA program graded A** (National) by CRISIL | AACSB, ACBSP and BGA Member
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books