46 Views

a body of mass 60 kg is inside a lift of masses 940 kg and presses the button on control panel the lift start moving upwards with an acceleration 1.5 metre per second square if g is equals to 10 metre per second inverse -2 to the tension in the supporting cable is


Abhishek Sisodiya 9th Dec, 2019
Answer (1)
Avishek Dutta 9th Dec, 2019
Let the mass of the lift is M
And the mass of the body be m
Now a be the acceleration of the lift
And g be the gravitational acceleration.
Now we have to find the tension .
Let the tension be T.
Hence T-(m+M)g=(m+M)a
T=(m+M)(g+a).
Now in the question we are given that
M=940
m=60
g=10
a=1.5
Hence T=1000*11.5=11500N

Related Questions

Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates and judiciaries
Amity University, Noida BBA A...
Apply
Ranked amongst top 3% universities globally (QS Rankings)
VIT Bhopal University | M.Tec...
Apply
M.Tech admissions open @ VIT Bhopal University | Highest CTC 52 LPA | Apply now
Amity University | M.Tech Adm...
Apply
Ranked amongst top 3% universities globally (QS Rankings).
Graphic Era (Deemed to be Uni...
Apply
NAAC A+ Grade | Among top 100 universities of India (NIRF 2024) | 40 crore+ scholarships distributed
Amity University Noida B.Tech...
Apply
Among Top 30 National Universities for Engineering (NIRF 2024) | 30+ Specializations | AI Powered Learning & State-of-the-Art Facilities
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books