Question : A can do a piece of work in 48 days. If B is 50% more efficient than A, then in how many days can B do the same work?
Option 1: 24
Option 2: 32
Option 3: 18
Option 4: 15
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Correct Answer: 32
Solution : Let the total work to be done = 1 Then, A's one day work= $\frac{\text{(total work)}}{ \text{(total days taken by A)}} =\frac{1}{48}$ B's one-day work = 150% of A's one-day work (because B is 50% more efficient) $=\frac{1}{48}\times\frac{150}{100}=\frac{1}{32}$ Total time taken by B to do total work= $\frac{1}{\frac{1}{32}}=32$ days Hence, the correct answer is 32.
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Question : A can do a piece of work alone in 40 days. A and B together can do the same work in 10 days. C is 50% less efficient than B. In how many days can A and C together complete the same work?
Option 1: 20 days
Option 2: 24 days
Option 3: 16 days
Option 4: 12 days
Question : Sachin is 12.5 percent less efficient than Rohit. If Sachin alone can finish a work in 24 days, then in how many days will Rohit alone finish the same work?
Option 1: 16 days
Option 2: 21 days
Option 3: 18 days
Option 4: 20 days
Question : X alone can complete a piece of work in 16 days, while Y alone can complete the same work in 24 days. They work on alternate days starting with Y. In how many days will 50% of the total work be completed?
Option 1: $\frac{24}{3}$ days
Option 2: $\frac{29}{3}$ days
Option 3: $\frac{32}{3}$ days
Option 4: 9 days
Question : A, B, and C together can do a piece of work in 6 days. A and B together can do the same work in 12 days. B alone can do the same work in 18 days. In how many days can A and C together do the same work?
Option 1: 9 days
Option 2: 10.5 days
Option 3: 8 days
Option 4: 7.5 days
Question : Reshma alone can do a work in 14 days. Bhavana is 40% more efficient than Reshma. The number of days, Bhavana alone will take to do the same piece of work is:
Option 1: 10 days
Option 2: 40 days
Option 3: 28 days
Option 4: 14 days
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