Question : A circle touches the side BC of a $\triangle A B C$ at P and also touches AB and AC produced at Q and R, respectively. If the perimeter of $\triangle A B C=26.4 \mathrm{~cm}$, then the length of AQ is:
Option 1: 17.6 cm
Option 2: 13.2 cm
Option 3: 15.4 cm
Option 4: 8.8 cm
Correct Answer: 13.2 cm
Solution : Given: Perimeter of triangle ABC = 26.4 cm Perimeter of triangle ABC = AB + BP + PC + AC We know that, AQ = AR, BP = BQ, CP = CR as they are tangents. ⇒ 26.4 = AB + BQ + CR + AC ⇒ 26.4 = AQ + AR The lengths of two tangents drawn from an external point to a circle are equal. Thus, AQ = AR ⇒ 26.4 = AQ + AQ ⇒ 26.4 = 2AQ ⇒ AQ = $\frac{26.4}{2}$ ⇒ AQ = 13.2 cm Hence, the correct answer is 13.2 cm.
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Question : A circle is inscribed in a triangle ABC. It touches sides AB, BC, and AC at points R, P, and Q, respectively. If AQ = 2.6 cm, PC = 2.7 cm, and BR = 3 cm, then the perimeter (in cm) of the triangle $\triangle \mathrm{ABC}$ is:
Option 1: 16.6
Option 2: 33.2
Option 3: 30
Option 4: 28
Question : A circle is inscribed in a triangle ABC. It touches sides AB, BC and AC at points R, P and Q, respectively. If AQ = 3.5 cm, PC = 4.5 cm and BR = 7 cm, then the perimeter (in cm) of the triangle $\triangle \mathrm{ABC}$ is:
Option 1: 30
Option 2: 15
Option 3: 28
Option 4: 45
Question : The sides AB, BC, and AC of a $\triangle {ABC}$ are 12 cm, 8 cm, and 10 cm respectively. A circle is inscribed in the triangle touching AB, BC, and AC at D, E, and F respectively. The difference between the lengths of AD and CE is:
Option 1: 4 cm
Option 2: 5 cm
Option 3: 3 cm
Option 4: 2 cm
Question : In a circle with centre O, AD is a diameter and AC is a chord. Point B is on AC such that OB = 7 cm and $\angle OBA=60^{\circ}$. If $\angle \mathrm{DOC}=60^{\circ}$, then what is the length of BC?
Option 1: $3 \sqrt{7} \mathrm{~cm}$
Option 2: $3.5 \mathrm{~cm}$
Option 3: $7 \mathrm{~cm}$
Option 4: $5 \sqrt{7} \mathrm{~cm}$
Question : In a triangle ABC, if $\angle B=90^{\circ}, \angle C=45^{\circ}$ and AC = 4 cm, then the value of BC is:
Option 1: $\sqrt{2} \mathrm{~cm}$
Option 2: $4 \mathrm{~cm}$
Option 3: $2 \sqrt{2} \mathrm{~cm}$
Option 4: $4 \sqrt{2} \mathrm{~cm}$
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