Question : A coconut tree swings with the wind in such a manner that the angle covered by its trunk is 18°. If the topmost portion of the tree covers a distance of 44 metres, find the length of the tree. ( $\tan 18°$ = 0.3249).
Option 1: 120 metres
Option 2: 210 metres
Option 3: 140 metres
Option 4: 70 metres
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Correct Answer: 140 metres
Solution : Let the length of the tree be $l$ metres. According to the question, $2\pi l×\frac{18°}{360°}=44$ ⇒ $\frac{44l}{7}×\frac{1}{20}=44$ ⇒ $l=140$ metres Hence, the correct answer is 140 metres.
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Question : A man standing on the bank of a river observes that the angle subtended by a tree on the opposite bank is 60°. When he retreats 36 m from the bank, he finds that the angle is 30°. The breadth of the river is:
Option 1: 15 metres
Option 2: 18 metres
Option 3: 16 metres
Option 4: 11 metres
Question : If the angle of elevation of the top of a pillar from the ground level is raised from 30° to 60°, the length of the shadow of a pillar of height $50\sqrt{3}$ metres will be decreased by:
Option 1: 60 metres
Option 2: 75 metres
Option 3: 100 metres
Option 4: 50 metres
Question : The upper part of a tree broken at a certain height makes an angle of 60° with the ground at a distance of 10 metres from its foot. The original height of the tree was:
Option 1: $20\sqrt{3}$ metres
Option 2: $10{\sqrt3}$ metres
Option 3: $10\left (2+{\sqrt3} \right)$ metres
Option 4: $10\left (2-{\sqrt3}\right)$ metres
Question : From the top of a 20 metres high building, the angle of elevation from the top of a tower is 60° and the angle of depression of its foot is at 45°, then the height of the tower is: $(\sqrt{3} = 1.732)$
Option 1: 45.46 metres
Option 2: 45.64 metres
Option 3: 54.64 metres
Option 4: 54.46 metres
Question : In $\triangle A B C, O$ is the point of intersection of the bisectors of $\angle B$ and $\angle A$. If $\angle B O C=108^{\circ}$, then $\angle B A O=$?
Option 1: 27°
Option 2: 40°
Option 3: 18°
Option 4: 36°
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