6 Views

Question : A consumer's utility function is $\mathrm{U}=\mathrm{X}^{\wedge} 2+\mathrm{Y}^{\wedge} 2$. If the consumer is currently consuming $\mathrm{X}=3$ and $\mathrm{Y}=4$, what is the marginal rate of substitution (MRS) of $\mathrm{X}$ for $\mathrm{Y}$ ?

Option 1: 3/4

Option 2: 4/3

Option 3: 9/16

Option 4: 16/9


Team Careers360 8th Jan, 2024
Answer (1)
Team Careers360 9th Jan, 2024

Correct Answer: 3/4


Solution : The correct answer is (a) $3 / 4$

To find the marginal rate of substitution (MRS) of $\mathrm{X}$ for $\mathrm{Y}$, we need to determine the rate at which the consumer is willing to trade off $\mathrm{X}$ for $\mathrm{Y}$ while keeping the utility constant. Mathematically, the MRS is given by the negative ratio of the marginal utilities of $\mathrm{X}$ and $\mathrm{Y}$ :
$
\operatorname{MRS}(\mathrm{X} \text { for } \mathrm{Y})=-\mathrm{MUx} / \mathrm{MUy}
$

Given the utility function $\mathrm{U}=\mathrm{X}^{\wedge} 2+\mathrm{Y}^{\wedge} 2$, we can calculate the marginal utilities as follows:
$
\begin{aligned}
& \mathrm{MUx}=\mathrm{dU} / \mathrm{dX}=2 \mathrm{X}=2 * 3=6 \\
& \mathrm{MUy}=\mathrm{dU} / \mathrm{dY}=2 \mathrm{Y}=2 * 4=8
\end{aligned}
$

Now, we can substitute the values into the formula for MRS:
$
\operatorname{MRS}(\mathrm{X} \text { for } \mathrm{Y})=-\mathrm{MUx} / \mathrm{MUy}=-6 / 8=-3 / 4
$

Since MRS is typically represented as a positive value, we take the absolute value:
$
\mid \operatorname{MRS}(\mathrm{X} \text { for } \mathrm{Y}) \mid=3 / 4
$

Related Questions

MAHE Manipal M.Tech 2025
Apply
NAAC A++ Accredited | Accorded institution of Eminence by Govt. of India | NIRF Rank #4
Graphic Era (Deemed to be Uni...
Apply
NAAC A+ Grade | Among top 100 universities of India (NIRF 2024) | 40 crore+ scholarships distributed
Amity University Noida B.Tech...
Apply
Among Top 30 National Universities for Engineering (NIRF 2024) | 30+ Specializations | AI Powered Learning & State-of-the-Art Facilities
JSS University Mysore BBA Adm...
Apply
NAAC A++ Accredited| Ranked #24 in University Category by NIRF
JSS University Noida MBA 2025
Apply
170+ Recruiters Including Samsung, Zomato, LG, Adobe and many more | Highest CTC 47 LPA
UPES B.Tech Admissions 2025
Apply
Ranked #42 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements | Last Date to Apply: 29th May
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books