2175 Views

A copper atom has 29 electrons revolving around the nucleus. A copper ball contains 4*10^23 atoms. What fraction of the electrons be removed to give the ball a of +9.6uc


charani 12th Nov, 2019
Answer (1)
Janakiram Sharma 17th Dec, 2019

Hello!

Given,

The charge of each  atom is  = 29 C

Total charge = 29 x 4 x 10 = 1160 C

Total Number of electrons in Cu = 1160

Then, total number of electrons in 9.6 C = 9 . 6 / 1.6 x 10 ^ -19 = 6 x 10 ^ 19

Therefore, required fraction of electrons removed =

6 x 10 ^ 19 / 1160 = 5 . 17 x 10 ^ 16.

Amity University Noida B.Tech...
Apply
Among Top 30 National Universities for Engineering (NIRF 2024) | 30+ Specializations | AI Powered Learning & State-of-the-Art Facilities
Amrita University B.Tech 2026
Apply
Recognized as Institute of Eminence by Govt. of India | NAAC ‘A++’ Grade | Upto 75% Scholarships
Amity University, Noida | Law...
Apply
700+ Campus placements at top national and global law firms, corporates and judiciaries
Great Lakes Institute of Mana...
Apply
Admissions Open | Globally Recognized by AACSB (US) & AMBA (UK) | 17.8 LPA Avg. CTC for PGPM 2025
Manav Rachna University Law A...
Apply
Admissions open for B.A. LL.B. (Hons.), B.B.A. LL.B. (Hons.) and LL.B Program (3 Years) | School of Law, MRU ranked No. 1 in Law Schools of Excelle...
Nirma University Law Admissio...
Apply
Grade 'A+' accredited by NAAC | Ranked 33rd by NIRF 2025
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books