Hello!!!!

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Given ,Mass,m=3gm =0.003kg

position ,x =3t-4t^2+t^3

by differentiating x,, we get V

v=dx/dt=3-8t+3t^2

dx=(3-8t+3t^2)dt

on differentiating v ,,we get a

a=dv/dt =( -8+6t)

now ,we know that work done ,,W =∫ F.dx

dw=F.dx

dw=(ma) .dx

dw=(0.003)(-8+6t).(3-8t+3t^2)dt

dw=(0.003)(18t^3-72t^2+82t-24)dt

On integrating both sides , we get

w=(0.003) ∫0 to 4(18t^3-72t^2+82t-24)dt,

by simplifying,we get

w=0.528 J

Hope it helps!!!!