Hello Aspirant,

Given Side of the cube, a = 7 cm

Hence area of the leftover cubical surface = 5a² = 5 x 7² = 245 cm²

Diameter of the hemisphere = 7 cm

=> radius of the hemisphere = 7/2 = 3.5 cm

Area of the hemispherical depression = 2πr²

= 2 x 22/7 x 3.5 x 3.5

= 77 cm²

Hence total surface area of the remaining portion

= 245 + 77

= 322 cm²

Hence the total surface area of the remaining solid is 322 cm²

I hope this will help you.

Feel free to ask any query!!

All the best !!