a horizontal force pulls a 20kg box at a constant speed along a horizontal floor if the coefficient of friction between the box and the floor is 0.25 how much work is done by the force F in moving the box through a distance of 2moption 49j {2} 98 {3} 147 {4} 196

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a horizontal force pulls a 20kg box at a constant speed along a horizontal floor if the coefficient of friction between the box and the floor is 0.25 how much work is done by the force F in moving the box through a distance of 2moption 49j {2} 98 {3} 147 {4} 196

Kapil 7th Sep, 2019

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Upendra Gupta 31st Oct, 2019

Hiii Kapil answer to your question is

Since the box is moved at a constant velocity,the applied force F just overcomes the frictional force f,i.e,

F=f=μmgF=f=μmg

∴∴ Work done W=FScosθ=μmgScos0W=FScosθ=μmgScos0

⇒0.25×20×9.8×2=98J

Hope you like the answer....keep asking we are always looking for you to help....may you have a very bright future

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