Question : A is the centre of a circle whose radius is 8 units, and B is the centre of a circle whose diameter is 8 units. If these two circles touch externally, then the area of the circle with diameter AB is:
Option 1: $36\pi$ sq. units
Option 2: $64\pi$ sq. units
Option 3: $144\pi$ sq. units
Option 4: $256\pi$ sq. units
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Correct Answer: $36\pi$ sq. units
Solution :
The distance between A and B is the sum of their radii = 8 + 4 = 12 units The diameter AB of the new circle is 12 units. The radius of the new circle is 6 units. The area of a circle, $= \pi r^2=\pi(6^2)=36\pi$ sq. units Hence, the correct answer is $36\pi$ sq. units.
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Question : Two circles touch each other externally. The radius of the first circle with centre O is 12 cm. Radius of the second circle with centre A is 8 cm. Find the length of their common tangent BC.
Option 1: $6 \sqrt{6} \mathrm{~cm}$
Option 2: $8 \sqrt{3} \mathrm{~cm}$
Option 3: $8 \sqrt{2} \mathrm{~cm}$
Option 4: $8 \sqrt{6} \mathrm{~cm}$
Question : The area of triangle with vertices A(0, 8), O(0, 0), and B(5, 0) is:
Option 1: 8 sq. units
Option 2: 13 sq. units
Option 3: 20 sq. units
Option 4: 40 sq. units
Question : Two circles touch each other externally. The radius of the first circle with centre O is 6 cm. The radius of the second circle with centre P is 3 cm. Find the length of their common tangent AB.
Option 1: $3\sqrt{2}$ cm
Option 2: $4\sqrt{2}$ cm
Option 3: $6\sqrt{3}$ cm
Option 4: $6\sqrt{2}$ cm
Question : There are two circles which touch each other externally. The radius of the first circle with centre O is 17 cm and the radius of the second circle with centre A is 7 cm. BC is a direct common tangent to these two circles, where B and C are points on the circles with centres O and A, respectively. The length of BC is:
Option 1: $2 \sqrt{118} $ cm
Option 2: $2 \sqrt{119} $ cm
Option 3: $2 \sqrt{113} $ cm
Option 4: $2 \sqrt{117}$ cm
Question : ABCD is a square inscribed in a circle of radius $r$. Then the total area (in square units) of the portions of the circle lying outside the square is:
Option 1: $\pi (r^{2}-4)$
Option 2: $2\pi (r ^{2}-1)$
Option 3: $\pi^{2} r(r-7)$
Option 4: $r^{2}(\pi -2)$
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