Question : A number increased by $22\frac{1}{2}$% gives 98. The number is:
Option 1: 45
Option 2: 18
Option 3: 80
Option 4: 81
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Correct Answer: 80
Solution : Given: A number increased by $22\frac{1}{2}$% gives 98. Let the number be 100. If we increase it by $22\frac{1}{2}$% we get = $(100+100×\frac{22.5}{100})=122.5$ Here, 122.5 is equivalent to 98 So, 100 is equivalent to $(\frac{98×100}{122.5})=\frac{98×100×10}{1225}=80$ Hence, the correct answer is 80.
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Question : If $\cot B=9 $, then what will be the value of $\sec ^2 B$?
Option 1: $\frac{98}{81}$
Option 2: $\frac{92}{81}$
Option 3: $\frac{42}{81}$
Option 4: $\frac{82}{81}$
Question : The average of $n$ numbers is $a$. The first number is increased by 2, the second one is increased by 4, the third one is increased by 8, and so on. The average of the new numbers is:
Option 1: $a+\frac{2^{n–1}–1}{n}$
Option 2: $a+\frac{2(2n–1)}{n}$
Option 3: $a+\frac{2^{n–1}}{n}$
Option 4: $a+\frac{2^{n}–1}{n}$
Question : If $x=2-2^{\frac{1}{3}}+2^{\frac{2}{3}}$, then find the value of $x^3-6 x^2+18 x$.
Option 1: 40
Option 2: 33
Option 3: 45
Option 4: 22
Question : If $(x+y):(x-y)=11:1$, find the value of $(\frac{5x+3y}{x-2y})$.
Option 1: $\frac{45}{4}$
Option 2: $\frac{4}{45}$
Option 3: $-\frac{45}{4}$
Option 4: $-\frac{4}{45}$
Question : If the radius of a sphere is increased by 2.5 decimetres (dm), then its surface area increases by 110 dm$^2$. What is the volume (in dm$^3$ ) of the sphere? (Take $\pi=\frac{22}{7}$)
Option 1: $\frac{13}{21}$
Option 2: $\frac{3}{7}$
Option 3: $\frac{4}{7}$
Option 4: $\frac{11}{21}$
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