A particle moves along X axis. The velocity of the particle as function of x is v^2 = 12x - 3x^3 ( in SI ) . Find velocity of particle at the instant when acceleration is 1.5ms^-2

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A particle moves along X axis. The velocity of the particle as function of x is v^2 = 12x - 3x^3 ( in SI ) . Find velocity of particle at the instant when acceleration is 1.5ms^-2

aruna kumari Samarla 22nd Feb, 2020

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Answer (1)

TANUJ JAIN 22nd Feb, 2020

Hey aspirant,

according to the given data -

differentiate v^2 = 12x - 3x on both sides we get,

Therefore 2vdv=9dx

Therefore dv/dx=9/2v

Therefore a=9/2v (Since dv/dx=acceleration)

Therefore v=9/2a

Therefore v=3m/s (putting a=1.5 m/s^2)

Hope this helped,

Thank You.

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