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a person has 50000 rupees which he wants to invest in two parts such that total annual interest at 10% on the first part and 12% on the second part amount to rupees , 5600 use Matrix multiplied to find the amount to be invested in each part


Mohit kumar 5th May, 2020
Answer (1)
Nimisha Gupta 15th May, 2020

Hello,

The answer to your question will be solved in the following manner:

Lets assume that the person invests "x" amount in the first part, then the remaining amount will be "50000- x" since the whole amount is 50000. Now we have investment amounts for both parts i.e. "x" for the first part and "50000- x" for the second part.

We know that the interest rates on the respective parts are 10% and 12%. So that will amount to 0.1 and 0.12 respectively.

The total amount of interest should result in 5600 so we have to form matrix in such a way that at the end of the year we get 5600 interest rate from 50000 invested.


The answer will be as follows: M

Matrix A = [x     50000- x]

Matrix B =    [0.1

0.12]



Solving the matrix we get

[x     50000-x ]  *  [0.1        =   5600

0.12]


[x * 0.1+ (50000-x)*0.12] = 5600

0.1x + 6000- 0.12x = 5600

0.02x = 400

x = 20000

Therefore the investment in first part will be20000 and investment in second part will be 50000-20000=30000.

Final answer will be 20000 and 30000 .


Hope it helps!

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