Question : A point D is taken from the side BC of a right-angled triangle ABC, where AB is hypotenuse. Then:
Option 1: AB2 + CD2 = BC2 + AD2
Option 2: CD2 + BD2 = 2AD2
Option 3: AB2 + AC2 = 2AD2
Option 4: AB2 = AD2 + BD2
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Correct Answer: AB2 + CD2 = BC2 + AD2
Solution : According to the question, Using Pythagoras theorem, In $\triangle$ABC AB2 = AC2 + BC2 ...........................................(i) In $\triangle$ACD AD2 = AC2 + CD2 AC2 = AD2 – CD2 ...........................................(ii) Put the value of AC2 in equation (i) AB2 = AD2 – CD2 + BC2 AB2 + CD2 = AD2 + BC2 Hence, the correct answer is AB2 + CD2 = BC2 + AD2.
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Question : ABC is a right angle triangle and $\angle ABC = 90^{\circ}$. BD is perpendicular on the side AC. What is the value of $(BD)^2$?
Option 1: $AD\times DC$
Option 2: $BC\times AB$
Option 3: $BC\times CD$
Option 4: $AD\times AC$
Question : ABCD is a quadrilateral in which BD and AC are diagonals. Then, which of the following is true:
Option 1: AB + BC + CD + DA < (AC + BD)
Option 2: AB + BC + CD + DA > (AC + BD)
Option 3: AB + BC + CD + DA = (AC + BD)
Option 4: AB + BC + CD + DA > 2(AC + BD)
Question : If ABC is an equilateral triangle and D is a point in BC such that AD is perpendicular to BC, then:
Option 1: AB : BD = 1 : 1
Option 2: AB : BD = 1 : 2
Option 3: AB : BD = 2 : 1
Option 4: AB : BD = 3 : 2
Question : ABC is an isosceles triangle having $\angle$ C = 90$^\circ$, if D is any point on AB, then AD2 + BD2 is equal to:
Option 1: CD2
Option 2: 2CD2
Option 3: 3CD2
Option 4: 4CD2
Question : x, y, and z are the sides of a triangle. If z is the largest side and x2 + y2 > z2, then the triangle is a:
Option 1: Isosceles right angled triangle
Option 2: Acute angled triangle
Option 3: Obtuse angled triangle
Option 4: Right angled triangle
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