Dear candidate

Given let the points A(-1,2) and B(3,-4)  and consider another two points P and Q such that P=(x,y) and Q=(a,b) and consider P and Q as the point of Trisection of line AB which means as they are point of trisection that means theoretically AP=PQ=QB P divides AB line in 1:2 ratio internally and Q divides AB in 2:1 ratio internally that means by section formula for internally is

=(lx2+mx1)/(l+m),(ly2+my1)/(l+m)

let (x1,y1)=A(-1,2) and (x2,y2)=B(3,-4)

Here P divides AB line in 1:2 ratio so l=1 and m=2 substitute the l=1,m=2,x1,y1,x2,y2 in the above section formula we get the point P and do the same to find Q which divides AB in 2:1 ratio by substituting l=2,m=1,x1,y1,x2,y2 we get another point Q

Hence solved.