Greeting Aspirant,

The power drawn will be P(r/z)^2. The same cannot be explained here, hence i have solved and uploaded a picture. Still i have tried to give the solution below:

In case of pure resistance circuit,

For pure resistor circuit, power

P=V^2/R⇒V^2=PR

When inductance is connected in series with resistance.

For L−R series circuit, power

P'=V^2/Z *cosθ=PR/Z . R/Z= P(R/Z)^2

The Image link for the same with diagram is below:

https://drive.google.com/file/d/1CbGKSqE4mWGRUZMurwJSR6iduUpHWqX8/view?usp=drivesdk

Best Of Luck For Future.