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A 44 Ω resistor is connected in series with a cell of internal resistance 4Ω and emf 12V. find the current flowing in the circuit.

PRADEEP KUMAR 11th Nov, 2021

Answer (1)

PRADEEP KUMAR 11th Nov, 2021

IR = ε – Ir

I= R+r

I=1248

I = 0.25 A

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