Hello!!!!

Hope you are doing great!!!!

Given mass of the rod = m

length of the rod= l

Potential energy is present at the center of the rod.So the length should be taken from the center to one of the edge of the rod,i.e l= l/2

As the angle is given,it will be x= l/2 sinθ

x=l/2 sin 30 ( since angle with the vertical  is 60 ,,so the angle with the horizontal is 30)

x=l/4

Potential energy = mgx

=mgl/4

Hope it helps!!!!