Dear student,

Your question is actually incomplete. Because you have not mentioned the density of solution. Without density of solution the molarity cannot be founded. So I am assuming the density of solution as 1.2gm/ml

10% w/w of glucose means 10 gm of solute ( glucose ) present in 100 gm of solution ( glucose + water ).

Glucose = C6H12O6 ( MM = 180 ).

So, volume of solution = 100/1.2 = 83.33 ml

Now, molarity is number of moles of solute present in 1000 ml of solution.

So, moles of solute ( Glucose ) = 10/180 = 1/18mol.

So, 1/18 mol of glucose is present in 83.33 ml of solution.

So, for 1000 ml of solution the miles of solute will be = 1×1000/18×83.33 {via unitary method }

So, the molarity will be = 0.667 M