Let the height of the pedestal be represented by line WX and height of the statue by the line XY .
Height of Statue = XY = 1.6m
Angle of elevation to top of statue from a point p on the ground = 60°
Angle of elevation to top of pedestal from a point p on the ground = 45°
To find the length WX :
Now as statue is perpendicular to ground angle is 90°
So WXP is a right angles triangle with one angle 45° and other 90° so other one has to be 45° , which shows it is an isosceles triangle and hence WX = WP .
Similarly YWP is also a right angled triangle .
tan60° = height of (pedestal + statue)/distance of point p from base of pedestal = (1.6+WX)/WP = (1.6+WX)/WX [Since WX = WP]
> √3 * WX = 1.6 + WX
> √3 * WX - WX = 1.6
> (√3 - 1) WX = 1.6
or WX = 1.6/(√3-1)
Question : A tower is broken at a point P above the ground. The top of the tower makes an angle of $60^\circ$ with the ground at Q. From another point R on the opposite side Q angle of elevation of point P is $30^\circ$. If QR = 180 m, what is the total height (in meters) of the tower?
Option 1: $90$
Option 2: $45\sqrt{3}$
Option 3: $45(\sqrt{3}+1)$
Option 4: $45(\sqrt{3}+2)$
Question : A pole of length 7 m is fixed vertically on the top of a tower. The angle of elevation of the top of the pole observed from a point on the ground is 60° and the angle of depression of the same point on the ground from the top of the tower is 45°. The height (in m) of the tower is:
Option 1: $7(2 \sqrt{3}-1)$
Option 2: $\frac{7}{2}(\sqrt{3}+2)$
Option 3: $7 \sqrt{3}$
Option 4: $\frac{7}{2}(\sqrt{3}+1)$
Question : The angle of elevation of the top of a tower from the top of a building whose height is 680 m is $45^{\circ}$ and the angle of elevation of the top of the same tower from the foot of the same building is $60^{\circ}$. What is the height (in m) of the tower?
Option 1: $340(3 + \sqrt3)$
Option 2: $310(3 - \sqrt3)$
Option 3: $310(3 + \sqrt3)$
Option 4: $340(3 - \sqrt3)$
Question : TF is a tower with point F on the ground. The angle of elevation of T from A is $\tan\;x^{\circ}=\frac{2}{5}$ and AF = 200 m. The angle of elevation of T from a nearer point B is $y^{\circ}$ with BF = 80 m. The value of $y$ is:
Option 1: 60$^{\circ}$
Option 2: 30$^{\circ}$
Option 3: 75$^{\circ}$
Option 4: 45$^{\circ}$
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile