Dear student,

Height of tap from ground = 5 m, let's assume g = 10m/s^2 for ease calculation.

Now, time taken by first drop to fall to ground :-
5 = ut + 1/2 gt^2

5 = 0 + 1/2 10 t^2 (because u=0)

Therefore t = 1 sec, i.e, first drop takes 1 second to reach the ground.

Now, water drops are falling at regular intervals.
So, as fourth drop immediately when the first drop reaches ground, so for each drop the time interval will be of 1/3 seconds.

Now, when the first drop falls on ground the second drop travels for 2/3 seconds.

So, the distance traveled by the second from the tap :-

s = ut + 1/2 gt^2
s = 1/2 10 (2/3)^2 = 20/9 m

So, distance of second drop from the ground = 5 - 20/9 = 25/9 =2.778m

Hindusthan Institute of Technology, Coimbatore

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