Question : A wire of resistance R is cut into 'n' equal parts. These parts are then connected in parallel. The equivalent resistance of the combination will be
Option 1: nR
Option 2: R/n
Option 3: n/R
Option 4: R/n2
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Correct Answer: R/n
Solution : The correct option is R/n.
The equivalent resistance of the combination may be determined using the formula:
1/R = (1/R₁) + (1/R₂) + (1/R₃) + ... + (1/Rₙ)
In this case, all the 'n' equal parts of the wire have the same resistance, which is R. Therefore, for 'n' parts connected in parallel, you can simplify the formula as follows:
1/R = n/R
Now, solve for R_eq:
R = R/n
So, the equivalent resistance of 'n' equal parts of the wire connected in parallel is R/n.
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Question : A wire of resistance R is melted and recast to half of its length, then the new resistance of the wire will be
Option 1: R/4
Option 2: R/2
Option 3: R
Option 4: 2R
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Option 1: 38.50 cm2
Option 2: 42.25 cm2
Option 3: 35 cm2
Option 4: 30.25 cm2
Question : A solid sphere of diameter 7 cm is cut into two equal halves. What will be the increase in its total surface area?
Option 1: 77 cm2
Option 2: 60.5 cm2
Option 3: 65.5 cm2
Option 4: 55 cm2
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Option 1: 5
Option 2: 6
Option 3: 7
Option 4: 8
Question : Which of the following laws, represented by the formula T2/R3, compares the orbital period and radius of the orbit of a planet with that of other planets?
Option 1: Hubble's Law
Option 2: Copernicus's Law
Option 3: Kepler's Third Law
Option 4: Bragg's Law
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