Question : ABC is a right angle triangle and $\angle ABC = 90^{\circ}$. BD is perpendicular on the side AC. What is the value of $(BD)^2$?
Option 1: $AD\times DC$
Option 2: $BC\times AB$
Option 3: $BC\times CD$
Option 4: $AD\times AC$
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Correct Answer: $AD\times DC$
Solution : Given: ABC is a right angle triangle and $\angle ABC = 90^{\circ}$. In $\triangle ADB$ and $\triangle BDC$, $\angle ADB=\angle BDC$ (Since $BD \perp AC$) $\angle ABD=\angle BCD$ $BD = BD$ (common) So, $\triangle ADB\sim\triangle BDC$ When two triangles are similar, their corresponding sides have the same proportion and their corresponding angles are congruent. ⇒ $\frac{AD}{DB}=\frac{BD}{DC}$ ⇒ $(BD)^2=AD\times DC$ Hence, the correct answer is $AD\times DC$.
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Question : ABCD is a quadrilateral in which BD and AC are diagonals. Then, which of the following is true:
Option 1: AB + BC + CD + DA < (AC + BD)
Option 2: AB + BC + CD + DA > (AC + BD)
Option 3: AB + BC + CD + DA = (AC + BD)
Option 4: AB + BC + CD + DA > 2(AC + BD)
Question : In $\triangle \mathrm{ABC}$, $\angle \mathrm{ABC} = 90^{\circ}$, $\mathrm{BP}$ is drawn perpendicular to $\mathrm{AC}$. If $\angle \mathrm{BAP} = 50^{\circ},$ what is the value of $\angle \mathrm{PBC}?$
Option 1: $30^{\circ}$
Option 2: $45^{\circ}$
Option 3: $50^{\circ}$
Option 4: $60^{\circ}$
Question : If ABC is an equilateral triangle and D is a point in BC such that AD is perpendicular to BC, then:
Option 1: AB : BD = 1 : 1
Option 2: AB : BD = 1 : 2
Option 3: AB : BD = 2 : 1
Option 4: AB : BD = 3 : 2
Question : $\triangle ABC$ and $\triangle PQR$ are two triangles. AB = PQ = 6 cm, BC = QR =10 cm, and AC = PR = 8 cm. If $\angle ABC = x$, then what is the value of $\angle PRQ$?
Option 1: $(180 ^{\circ}–x)$
Option 2: $x$
Option 3: $(90 ^{\circ}–x)$
Option 4: $(90 ^{\circ}+x)$
Question : $D$ is a point on the side $BC$ of a triangle $ABC$ such that $AD\perp BC$. $E$ is a point on $AD$ for which $AE:ED=5:1$. If $\angle BAD=30^{\circ}$ and $\tan \left ( \angle ACB \right )=6\tan \left ( \angle DBE \right )$, then $\angle ACB =$
Option 3: $60^{\circ}$
Option 4: $15^{\circ}$
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