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age of the father is 30 years more than his son after 5 years the product of their ages become 400 find the present age of the both son and father


Md Rafi 4th Dec, 2025
Answers (2)
Sachin Saravanan 9th Dec, 2025

Hello aspirant,

Let the son's present age be x. Then the father's age is x+30.

After 5 years :

Son = x+5, Father = (x+35)

Their product is 400:

(x+5)(x+35) = 400

x^2 + 40x +175 =400

x^2+40x-225 = 0

Solving gives x=5.

So the son is 5 years old and the father is 35 years old.

FOR REFERENCE : https://school.careers360.com/articles/math-question-solver

Hope the details will help you.

THANK YOU

Sachin Saravanan 9th Dec, 2025

Hello aspirant,

Let the son's present age be x. Then the father's age is x+30.

After 5 years :

Son = x+5, Father = (x+35)

Their product is 400:

(x+5)(x+35) = 400

x^2 + 40x +175 =400

x^2+40x-225 = 0

Solving gives x=5.

So the son is 5 years old and the father is 35 years old.

FOR REFERENCE : https://school.careers360.com/articles/math-question-solver

Hope the details will help you.

THANK YOU

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