S-c = c/10
1 1/9 % = 10/9% = 10/900= 1/90
S+10 - ( c+20) = (c+20) /90
S+10 - c-20 = (c+20) /90
S - c +10 -20 = (c+20) /90
S - c -10 = (c+20) /90
S - c =( (c+20) /90 )
S - c =10 + ( (c+20) /90)
c/10 = 10 + ( (c+20) /90)
(c/10 ) - ( (c+20) /90) =10
(9c/90 ) - ( (c+20) /90) =10
(9c-c-20) /90) =10
(8c-20) /90) =10
8c -20 =900
8c = 920
C = 115
Let initial cost price (CP) be x.
So initial selling price (SP) will be 110% of x = 11x/10.
Now, new CP = x+20
New SP = 11x/10 + 10
New profit = New SP - New CP
= 11x/10 + 10 - x - 20
= x/10 - 10
Profit percentage = New profit/ New CP x 100
= (x/10 - 10).100 / (x + 20)
= 10(x-100) / (x + 20)
Equating it with 10/9 % as given in the question:
10(x-100)/(x+20) = 10/9
=> 9(x-100) = x+20
=> 9x - 900 = x + 20
=> 8x = 920
=> x = 920/8 = 115
So the original cost price was Rs 115.
Question : If an article is sold at $\frac{9}{10}th$ of its usual selling price, 20% profit would be made on it. Find the profit percentage which would have been made on it on selling it at its usual selling price.
Option 1: 33.33%
Option 2: 25%
Option 3: 30%
Option 4: 20%
Question : An article is sold at a 5 percent loss. If its cost price is decreased by Rs. 20 and the selling price is increased by Rs. 13, then a profit of 10 percent is earned on it. What is the original selling price of the article?
Option 1: Rs 266.66
Option 2: Rs 221.66
Option 3: Rs 283.33
Option 4: Rs 250
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