Question : An epidemic broke out in a village where 5% of the population died. Of the remaining population, 20% fled in panic. If the present population is 4655, what was the original population of the village?
Option 1: 6000
Option 2: 6125
Option 3: 5955
Option 4: 5995
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Correct Answer: 6125
Solution : Let the village's initial population be 100$x$. The population after death = 100$x$ – (5% of 100$x$) = 100$x$ – 5$x$ = 95$x$ After fleeing out, the population = 95$x$ – (20% of 95$x$) = 95$x$ – ($\frac{20}{100}$ × 95) = 95$x$ – 19$x$ = 76$x$ According to the question, 76$x$ = 4655 ⇒ $x$ = $\frac{4655}{76}$ = 61.25 So, the original population is (61.25 × 100) = 6125 Hence, the correct answer is 6125.
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Question : The population of a certain village increases by 5% annually. Its present population is 8200. After two years the population will be (approximately):
Option 1: 9200
Option 2: 9246
Option 3: 9040
Option 4: 9161
Question : The population of the village was 12,000 two years ago. If it increased by 2.5% and 3%, respectively, in the last two years, then what is the present population of the village?
Option 1: 12,669
Option 2: 12,607
Option 3: 12,652
Option 4: 12,731
Question : The population of the village in 2019 was 30,000. The increase in population rate was 15% and 25%, respectively, from the year 2019 to 2020 and 2020 to 2021. What was the population in the year 2021?
Option 1: 42,000
Option 2: 42,325
Option 3: 42,523
Option 4: 43,125
Question : The population of a city increases compounded by 10% annually. The present population of this city is 1,33,100. What was the population of the city 2 years ago?
Option 1: 1,01,000
Option 2: 1,10,000
Option 3: 1,21,000
Option 4: 1,00,000
Question : In a village, 30% of the population is literate. If the total population is 6,600, what is the number of illiterate people?
Option 1: 1980
Option 2: 4620
Option 3: 2200
Option 4: 3280
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