Question : $\text{PS}$ and $\text{PT}$ are two tangents from a point $\text{P}$ outside the circle with centre $\text{O}$. If $\text{S}$ and $\text{T}$ are points on the circle such that $\angle SPT=130^{\circ}$, then the degree measure of $\angle OST$ is equal to:
Option 1: $25^{\circ}$
Option 2: $55^{\circ}$
Option 3: $65^{\circ}$
Option 4: $35^{\circ}$
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Correct Answer: $65^{\circ}$
Solution : $\angle SPT = 130^{\circ}$ And also, $\angle PSO = \angle PTO = 90^{\circ}$ Now, PTOS is a quadrilateral. $\therefore$ $\angle P + \angle O + \angle S + \angle P = 360^{\circ}$ ⇒ $\angle O = 360^{\circ} - 310^{\circ} = 50°$ Now to calculate $\angle OST$. $\angle OST$ will be equal to $\angle OTS$. In $\triangle OST$, $\angle OST + \angle OTS + \angle TOS = 180^{\circ}$ ⇒ $2\angle OST = 180^{\circ} - 50^{\circ}=130^{\circ}$ $\therefore\angle OST = 65^{\circ}$ Hence, the correct answer is $65^{\circ}$.
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Question : In $\Delta ABC$, the external bisector of the angles, $\angle B$ and $\angle C$ meet at the point $O$. If $\angle A = 70^\circ$, then the measure of $\angle BOC$:
Option 1: $55^\circ$
Option 2: $75^\circ$
Option 3: $60^\circ$
Option 4: $50^\circ$
Question : AB and BC are two chords of a circle with centre O. Both chords are on either side of the centre O. Point A and point C are connected to the centre O, such that $\angle B A O=36^{\circ}$ and $\angle B C O=48^{\circ}$. What is the degree measure of the angle subtended by the minor arc AC at the centre O?
Option 1: 136°
Option 2: 144°
Option 3: 120°
Option 4: 168°
Question : In $\triangle ABC$, the internal bisectors of $\angle B$ and $\angle C$ meet at point $O$. If $\angle A = 80^\circ$, then $\angle BOC$ is equal to:
Option 1: $100^\circ$
Option 2: $120^\circ$
Option 3: $130^\circ$
Option 4: $140^\circ$
Question : If in a $\triangle$PQR, $\angle$P = $88^\circ$, PQ and PR are produced to points S and T respectively. If the bisectors of $\angle$SQR and $\angle$TRQ meet at the point O. Find $\angle$QOR.
Option 1: $42^\circ$
Option 2: $46^\circ$
Option 3: $44^\circ$
Option 4: $48^\circ$
Question : $\mathrm{O}$ is the centre of a circle and $\mathrm{A}$ is a point on a major arc $\mathrm{BC}$ of the circle. $\angle \mathrm{BOC}$ and $\angle \mathrm{BAC}$ are the angles made by the minor arc $\mathrm{BC}$ on the centre and circumference, respectively. If $\angle \mathrm{ABO}=40^{\circ}$ and $\angle \mathrm{ACO}=30^{\circ}$, then find $\angle \mathrm{BOC}$.
Option 1: $130^{\circ}$
Option 2: $140^{\circ}$
Option 3: $120^{\circ}$
Option 4: $150^{\circ}$
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