FIRST OF ALL 79 PERCENTILE IS A VERY LOW SCORE BUT AS NTA HAS GIVEN YOU TWO OPPORTUNITIES THIS TIME SO I THINK YOU SHOULD TRY YOUR BEST TO SCORE MORE THAN THE PREVIOUS ONE AND WHICHEVER WILL BE YOUR BEST SCORE, THAT PERCENTILE WILL BE USED TO CALCULATE YOUR RESULT.IF YOU WANT A GOOD COLLEGE THEN I AM REALLY SORRY TO SAY YOU CAN'T GET WITH THIS SCORE SO TRY YOUR BEST AND GIVE YOUR SECOND JEE MAIN WITH FULL OF ENERGY.FURTHERMORE, TO DETERMINE JEE MAIN 2019 RESULTS AND RANKLIST, THE AGENCY WILL ADOPT THE PROCESS OF NORMALIZATION WHICH WILL BE BASED ON PERCENTILE CALCULATION.THUS, DERIVING ONE'S RANK FROM THE PERCENTILE SCORE OF THE FIRST ATTEMPT IS NOT POSSIBLE AS THE EXAM IS BEING CONDUCTED TWICE.THEREFORE, WITHOUT TAKING MUCH OF YOUR WORRY YOU CAN START PREPARING FOR YOUR APRIL SESSION EXAM.BEST OF LUCK FOR IT.

• Rank Formula = (100 - your total score) X 874469/100.
• Your expected rank is 183638 by using above formula.

Hello Somesh

Well, it's very difficult as of now,to predict the cutoff for colleges of JEE mains and for jee advance based on percentile.You can first calculate your rank by rank=(100-percentile)*874469/100.With this rank,you can compare previous year's cutoff for different colleges and can predict some of the colleges you may be getting and also the advance cut off.But remember this is not the final rank.It will change based on the april session of mains.To further predict colleges visit https://engineering.careers360.com/jee-main-college-predictor  .Hope this helps.

Good Luck